How do you solve $6( 4+ c ) = 5( c - 5)$ ?

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Answer 1 · 2018-03-16T03:53:28

$c=-49$

Well, to start off, you would first use the distributive property to get rid of the parentheses from both sides.

$6(4+c) = 5(c-5)$

becomes

$24+6c = 5c -25$

Next, you would want to isolate the variable by getting all of them to one side of the equal sign and the non-variables on the other.

So from

$24+6c = 5c-25$

you would subtract $5c$ from both sides and $24$ from both sides

$24-24 +6c -5c = 5c-5c -25 -24$

The $24$ 's cancel out and so do the $5c$ 's. You are then left with

$6c-5c = -25-24$

Subtract $5c$ from $6c$ , add $-24$ and $-25$ together to get $-49$ , and that is your answer!

$c = -49$

How do you solve 6( 4+ c ) = 5( c - 5)6( 4+ c ) = 5( c - 5)?