Question

How do you factor `11x^2+11xy+4x+4y`?

Answer 1

A bit rusty with factoring, but I'm pretty sure...

Explanation:

`11x^2 + 11xy + 4x + 4y`

(Use grouping.)

`11(11x^2 + 11xy) + 4(4x + 4y)`

`(x + y)(11x + 4)`

Answer 2

`(x+y)(11x+4)`

Explanation:

`"factorise in groups"`

`color(red)(11x)(x+y)color(red)(+4)(x+y)`

`"take out "color(blue)"common factor "(x+y)`

`=(x+y)(color(red)(11x+4))`

`rArr11x^2+11xy+4x+4y=(x+y)(11x+4)`