How do you simplify #5/(6x^3 + x)div(x^2-12x)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Aroz A. Mar 22, 2018 #=5/(x^2(6x^2+1)(x-12))# Explanation: #5/(6x^3+x) ÷ (x^2 -12x )# #= 5/(6x^3+x) * 1/(x^2 -12x )# #= 5/ (6x^5-72x^4+x^3-12x^2)# #=5/(x^2(6x^3-72x^2+x-12)# #=5/(x^2(6x^2(x-12)+1(x-12)))# #=5/(x^2(6x^2+1)(x-12))# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1638 views around the world You can reuse this answer Creative Commons License