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How do you factor $x^{4} + 2 x^{3} - 3 x - 6$ $x^4 + 2x^3 - 3x - 6$ ?

1 Answer

Mar 24, 2018

$(x + 2) (x^{3} - 3)$ $(x+2)(x^3-3)$

Explanation:

$x^{4} + 2 x^{3} - 3 x - 6$ $x^4 + 2x^3 - 3x -6$
$x^{3} (x + 2) - 3 (x + 2)$ $x^3(x + 2) -3 (x +2)$ <- Factor out the GCF: $x^{3}$ $x^3$ for the first pair and $- 3$ $-3$ for the second pair
$(x + 2) (x^{3} - 3)$ $(x+2)(x^3-3)$ <- Factor out the binomial $(x + 2)$ $(x+2)$

Hope this helps!

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