Question

How do you graph `y=-5cos(1/2)x`?

Answer 1

You have an inverted graph of cosine with a vertical stretch factor of 5 was a horizontal stretch factor of 2, it has no shift.

Explanation:

I assume you mean:

`y = − 5 cos ( 1/ 2 x)`

if so standard form is:

`acos(bx -c) + d`

`a = "amplitude (vertical stretch)"`
`b = "horizontal stretch"`
`c = "horizontal shift"`
`d = "vertical shift"`

if `a <0` graph is inverted.

so you have an inverted graph of cosine with a vertical stretch factor of 5 was a horizontal stretch factor of 2, it has no shift.