How do you shift and graph $y=-3+sinx$ ?

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Answer 1 · 2014-10-31T23:20:19

The period of $sin$ is $2pi$ .

The $-3$ is applied to the result of $sin(x)$ which affects the $y$ value.

All of the points will be shifted down $3$ units.

Rely on your knowledge of the unit circle to figure out the values of sin on the $x$ and $y$ axis.

$f(0)=-3+sin(0)=-3+0=-3 -> (0,-3)$

$f(pi/2)=-3+sin(pi/2)=-3+1=-2 -> (pi/2,-2)$

$f(pi)=-3+sin(pi)=-3+0=-3 -> (pi,-3)$

$f((3pi)/2)=-3+sin((3pi)/2)=-3-1=-4 -> ((3pi)/2,-4)$

$f(2pi)=-3+sin(2pi)=-3+0=-3->(2pi,-3)$

Enter the function into the calculator

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Set the interval, XMIN and MAX , from $[0,2pi] -> 2pi=6.283185307$

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Press the GRAPH button

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How do you shift and graph y=-3+sinxy=-3+sinx?