How do you graph $y=3sin(1/2)x$ ?

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Answer 1 · 2018-04-01T05:25:30

As below.

$y = 3 sin (x/2)$

Standard form of the equation is $y = A sin (Bx - C) + D$

$Amplitude = |A| = 3$

$"Period " = (2pi) / |B| = (2pi) / (1/2) = 4ppi$

$"Phase Shift " = C / B = 0$

$"Vertical Shift " = D = 0$

graph{3 sin(x/2) [-10, 10, -5, 5]}

How do you graph y=3sin(1/2)xy=3sin(1/2)x?