How do you solve #3(2x - 1) - 2(3x +4) = 11x#?

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Answer 1 · 2018-05-26T19:45:52

#x=-1#

Expanding
#6x-3-6x-8=11x#
This gives
#-11=11x#
#x=-1#

Answer 2 · 2018-05-26T19:49:54

#x=-1#

#3(2x-1) =6x-3#

#2(3x+4) = 6x+8#

So

#6x-3 -(6x+8)=11x#

#6x-3-6x-8 =11x#

#-3-8=11x#

#-11 =11x#

This gives

#(-11)/11 =(11x) /11#

#x=-1#

Answer 3 · 2018-05-26T19:51:48

#x=-1#

Expand your brackets first...

#3(2x-1)=6x-3#
#-2(3x+4)=-6x-8#

This give you...

#6x-3-6x-8=11x#

Then you move all the like terms to each sides...

#-3-8=11x+6x-6x#

Then simplfy by cancelling out like terms...

#-11=11x#

#x=-11/11#

#x=-1#