How do you solve and graph #|x + 2| ≤ 3#?

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Answer 1 · 2018-06-12T03:36:30

#-5<=x<=1#

#|x + 2| ≤ 3#

You have to solve to equations:

#x + 2 <= 3#

#x <= 1#

and

#x + 2 >=-3#

#x>=-5#

Graph will be this with a horizontal line at #y=3# everything below the line inside the "v" is the solution.

graph{abs(x+2) [-12.75, 7.25, -2.12, 7.88]}