How do you solve and graph $|x + 2| ≤ 3$ ?

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Answer 1 · 2018-06-12T03:36:30

$-5<=x<=1$

$|x + 2| ≤ 3$

You have to solve to equations:

$x + 2 <= 3$

$x <= 1$

and

$x + 2 >=-3$

$x>=-5$

Graph will be this with a horizontal line at $y=3$ everything below the line inside the "v" is the solution.

graph{abs(x+2) [-12.75, 7.25, -2.12, 7.88]}

How do you solve and graph |x + 2| ≤ 3|x + 2| ≤ 3?