What is the trigonometric form of $7 e^{\frac{5 π}{12} i}$ $7 e^( ( 5 pi)/12 i )$ ?

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Answer 1 · 2018-08-02T02:05:20

$7 e^{(\frac{5 π}{12}) i} = 7 \cdot (cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12}))$ $7 e^(((5pi)/12)i) = 7 * ( cos((5pi)/12) + i sin((5pi)/12))$

Trigonometric form of $e^{i x}$ $e^ (ix)$ , using Euler's Equation, is given by

$e^{i x} = cos x + i sin x$ $e^ (ix) = cos x + i sin x$

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$z = | z | e^{i x} = | z | \cdot (cos θ + i sin θ)$ $z = |z| e^(i x) = |z| * (cos theta + i sin theta)$

$7 e^{(\frac{5 π}{12}) i} = 7 \cdot (cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12}))$ $7 e^(((5pi)/12)i) = 7 * ( cos((5pi)/12) + i sin((5pi)/12))$

What is the trigonometric form of 7e5π12i 7 e^( ( 5 pi)/12 i ) ?