The volume of cubic shape and the area of a square are equal to 64.A student is asked to find cost of a boundary of a rectangular field whose length is side of cube and breadth is side of square,if the cost is R's 15 per unit?

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Answer 1 · 2018-08-04T06:10:34

$cost of boundary = (2 \cdot l + 2 \cdot b) \cdot 15 = R s 360 /=$ $color(violet)("Cost of boundary " = (2*l + 2 * b) * 15 = Rs 360"/="$

$Vol. of cube V_{c} = 64 or side a_{c} = \sqrt[3]{64} = 4$ $"Vol. of cube " V_c = 64 " or side " a_c = root 3 64 = 4$

$Area of square A_{s} = 64 or side a_{s} = \sqrt{64} = 8$ $"Area of square " A_s = 64 " or side " a_s = sqrt 64 = 8$

$Now the rectangular field will have Length l = 8, breadth b = 4$ $"Now the rectangular field will have Length l = 8, breadth b = 4"$

$cost of boundary = (2 l + 2 b) \cdot cost per unit$ $"Cost of boundary " = (2 l + 2 b) * "cost per unit"$

$cost of boundary = (2 \cdot 8 + 2 \cdot 4) \cdot 15 = R s 360 /=$ $color(violet)("Cost of boundary " = (2*8 + 2 * 4) * 15 = Rs 360"/="$