How do you graph $y = 4 cos (x + 1) - 2$ $y=4cos(x+1)-2$ ?

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Answer 1 · 2018-08-06T04:32:56

As below.

Standard form of a cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

$y = 4 cos (x + 1) - 2$ $y = 4 cos (x + 1) - 2$

$A = 4, B = 1, C = - 1, D = - 2$ $A = 4, B = 1, C = -1, D = -2$

$A m p l i t u d e = | A | = 4$ $Amplitude = |A| = 4$

$"Period ' = (2pi) / |B| = 2pi$

$"Phase Shift ' = -C / B = 1, color(crimson)(" 1 to the RIGHT"$

$"Vertical Shift ' = -2$

Knowing the above 4 parameters, we can draw thegraph.

graph{4 cos(x + 1) - 2 [-10, 10, -5, 5]}

How do you graph y=4cos(x+1)-2y=4cos(x+1)−2y=4cos(x+1)-2?