Question

Question #f2762

Answer 1

The final temperature is -175.9 Celsius degrees.

`(V_(1))/(T_(1))=(V_2)/T_(2)`

`V_(1)` = 10ml
`T_(1)` = 80 + 273 = 353K

`V_(2)` = 2.75 ml
`T_(2)` is unknown.

`T_(2)=(V_(2)T_(1))/(V_(1))`

`T_2=(2.75xx353)/(10)=97.1K`

`T_2=97.1 - 273 =175.9` deg Celsius.