Question #94f10

2 Answers
Mar 28, 2016

theta = (1/3)(+-(2n+1)pi-pi/2)θ=(13)(±(2n+1)ππ2), n = 0, 1, 2, 3..= pi/6, 5pi/6, 9pi/6, 13pi/6, .... The negative solutions are -3pi/6, -7pi/6, -11pi/6, ....

Explanation:

The general value of cos^(-1)(-1) = an odd multiple of pi.

So, 3theta+pi/2 = an odd multiple of pi = +-(2n+1)pi, n = 0, 1, 2, 3, ...

Positive solutions are pi/6, 5pi/6, 9pi/6, 13pi/6, ...
The negative solutions are -3pi/6, -7pi/6, -11pi/6, ....

Mar 28, 2016

t = pi/2 + k.pi

Explanation:

Trig unit circle gives -->
cos (3t + pi/2) = - 1 = cos pi
3t + pi/2 = +- pi
a. 3t = pi - pi/2 = pi/2. ---> t = (3pi)/2
b. 3t = -pi - pi/2 = -(3pi)/2, or (pi/2) --> co-terminal
General answers:
t = pi/2 + k.pi