A gas enclosed in a piston that has a volume of $245 \cdot m L$ $245*mL$ at $0$ $0$ $^{\circ} C$ $""^@C$ , will express what volume at $95$ $95$ $^{\circ} C$ $""^@C$ ?

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A gas enclosed in a piston that has a volume of $245 \cdot m L$ $245*mL$ at $0$ $0$ $^{\circ} C$ $""^@C$ , will express what volume at $95$ $95$ $^{\circ} C$ $""^@C$ ?

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Answer 1 · 2016-04-18T06:09:45

At constant pressure, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1=V_2/T_2$

Explanation:

The above was simply a restatement of Charles' Law.

Given your problem, and converting the temperatures to absolute values:

$V_{2} = T_{2} \times \frac{V_{1}}{T_{1}}$ $V_2=T_2xxV_1/T_1$ $=$ $=$ $(273 + 95) \cdot K \times \frac{245 \cdot m L}{(273 + 18) \cdot K}$ $(273+95)*Kxx(245*mL)/((273+18)*K)$ $≅ 300 \cdot m L$ $~=300*mL$

Note that for these problems I am obliged to turn temperatures into absolute temperatures (why? because the Gas Laws assume absolute temperatures). I am NOT obliged to use standard volumes if I am consistent - I could have used pints and gills if I knew what they meant! Thus a measurement in millilitres is quite acceptable.

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A gas enclosed in a piston that has a volume of $245 \cdot m L$ $245*mL$ at $0$ $0$ $^{\circ} C$ $""^@C$ , will express what volume at $95$ $95$ $^{\circ} C$ $""^@C$ ?

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A gas enclosed in a piston that has a volume of 245⋅mL245*mL at 00 ∘C""^@C, will express what volume at 9595 ∘C""^@C?

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A gas enclosed in a piston that has a volume of $245 \cdot m L$ $245*mL$ at $0$ $0$ $^{\circ} C$ $""^@C$ , will express what volume at $95$ $95$ $^{\circ} C$ $""^@C$ ?