Question #2ea88

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Question #2ea88

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Answer 1 · 2016-05-19T13:15:44

$36 {inches}^{2}$ $36" inches"^2$

Explanation:

Area of a right triangle $\to \frac{1}{2} \times base \times height$ $->1/2xx " base "xx" height"$

There are 2 sides wo we have

$2 [\frac{1}{2} \times base \times height] \to 2 [\frac{1}{2} \times 4 \times 3] = 12$ $2[1/2xx " base "xx" height"] -> 2[1/2xx4xx3]=12$
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$Base \to 4 \times 2 = 8$ $"Base "->4xx2=8$

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$Back \to 3 \times 2 = 6$ $"Back "-> 3xx2 =6$

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Slope using Pythagoras

$2 \times \sqrt{3^{2} + 4^{2}} = 2 \sqrt{25} = 10$ $2xxsqrt(3^2+4^2)" "=" "2sqrt(25)" " =" " 10$

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Total: $12 + 8 + 6 + 10 = 36 {inch}^{2}$ $" "12+8+6+10 = 36 " inch"^2$

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Question #2ea88

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