Question #2e63a

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Question #2e63a

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Answer 1 · 2016-06-24T16:20:08

Referring to the same frame, the second $y = x^{2}$ $y = x^2$ graph is the parabola with vertex at O, axis along y-axis and focus at $(0, \frac{1}{4})$ $(0, 1/4)$ . The 1st $y = x^{2} - 3$ $y=x^2-3$ graph is this brought down, by 3 units,

Explanation:

Referring to the same frame of axes, for both the graphs, the second

$y = x^{2}$ $y = x^2$ graph is the parabola with vertex at O, axis along y-axis

and focus at $(0, \frac{1}{4})$ $(0, 1/4)$ . The graph for the first parabola $y = x^{2} - 3$ $y=x^2-3$ is

obtained by moving the second down, by 3 units,

The parabolas are of the same size $a = \frac{1}{4}$ $a = 1/4$ . They are coaxial,

along y-axis, upwards..

The vertex of the first $y + 3 = x^{2}$ $y+3= x^2$ is at $(0, - 3)$ $(0, -3)$ and its focus is at
$(0, - \frac{11}{4})$ $(0, -11/4)$ .

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Question #2e63a

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