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Question #465f7

1 Answer

Oct 13, 2016

$f'(x) = -sinx$

Explanation:

$f(x) = (sin^2(x))/(1-cos(x))$

$= (1-cos^2x)/(1-cosx)$

$= ((1-cosx)(1+cosx))/(1-cosx)$

$= 1+cosx$ .

So,

$f'(x) = -sinx$ .

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