How do you determine if the summation n^n/(3^(1+2n))nn31+2n from 1 to infinity is convergent or divergent?

1 Answer
Mar 4, 2015

The terms of this series are all positive, so the series is regular, that means that is divergent or convergent.
Since n^nnn is an infinite of higher order of 3^(1+2n)31+2n,

lim_(nrarr+oo)n^n/3^(1+2n)=+oo,

the necessary condition (it has to be 0) failed, so it is divergent.