How do you use the Root Test on the series sum_(n=1)^oo((n^2+1)/(2n^2+1))^(n) ?

1 Answer
Oct 16, 2014

Let a_n=({n^2+1]/{2n^2+1})^n.

By Root Test,

lim_{n to infty}root[n]{|a_n|}=lim_{n to infty}root[n]{|({n^2+1}/{2n^2+1})^n|}

by cancelling out the nth-root and the nth-power,

=lim_{n to infty}{n^2+1}/{2n^2+1}

(Note: the absolute value is not necessary since it is already positive.)

by dividing by n^2,

=lim_{n to infty}{1+1/n^2}/{2+1/n^2}={1+0}/{2+0}=1/2<1

Hence, the series converges.

I hope that this was helpful.