Question #3ca54 Precalculus Polar Equations of Conic Sections Writing Polar Equations for Conic Sections 1 Answer Cem Sentin Feb 28, 2018 #y^2=25-10x# Explanation: #r=5/(1+cost)# #r*(1+cost)=5# #r+rcost=5# After using #r=sqrt(x^2+y^2)# and #rcost=x# transforms, #sqrt(x^2+y^2)+x=5# #sqrt(x^2+y^2)=5-x# #x^2+y^2=(5-x)^2# #x^2+y^2=x^2-10x+25# #y^2=25-10x# Answer link Related questions How do you identify conic sections? What is the meaning of conic section? What is the standard equation of a circle? What is the standard equation of a parabola? What is the standard equation of a hyperbola? Which conic section has the polar equation #r=1/(1-cosq)#? Which conic section has the polar equation #r=2/(3-cosq)#? Which conic section has the polar equation #r=a sintheta#? How do you find a polar equation for the circle with rectangular equation #x^2+y^2=25#? What are the polar coordinates of #(x-1)^2-(y+5)^2=-24#? See all questions in Writing Polar Equations for Conic Sections Impact of this question 1300 views around the world You can reuse this answer Creative Commons License