A $300 \cdot m L$ $300mL$ volume gas at $0.500 \cdot a t m$ $0.500atm$ in a piston, is compressed to $0.750 \cdot a t m$ $0.750*atm$ . What is the new volume?

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A $300 \cdot m L$ $300mL$ volume gas at $0.500 \cdot a t m$ $0.500atm$ in a piston, is compressed to $0.750 \cdot a t m$ $0.750*atm$ . What is the new volume?

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Answer 1 · 2017-08-03T07:52:56

$V_{2} = 200 \cdot m L$ $V_2=200*mL$

Explanation:

Old $Boyle's Law$ $"Boyle's Law"$ holds that for a given quantity of gas, at constant temperature, $P \propto \frac{1}{V}$ $Pprop1/V$ , and thus $P V = k$ $PV=k$ , where $k$ $k$ is some constant........

And it follows that $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , and.........

$V_{2} = \frac{P_{1} V_{1}}{P_{2}}$ $V_2=(P_1V_1)/P_2$ , which clearly has the units of volume as required.....

Here $V_{2} = \frac{300 \cdot m L \times 0.500 \cdot a t m}{0.750 \cdot a t m}$ $V_2=(300*mLxx0.500*atm)/(0.750*atm)$

$= 200 \cdot m L$ $=200*mL$ , volume is reduced as expected..........

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A $300 \cdot m L$ $300mL$ volume gas at $0.500 \cdot a t m$ $0.500atm$ in a piston, is compressed to $0.750 \cdot a t m$ $0.750*atm$ . What is the new volume?

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Explanation:

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A 300⋅mL300*mL volume gas at 0.500⋅atm0.500*atm in a piston, is compressed to 0.750⋅atm0.750*atm. What is the new volume?

1 Answer

Explanation:

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A $300 \cdot m L$ $300mL$ volume gas at $0.500 \cdot a t m$ $0.500atm$ in a piston, is compressed to $0.750 \cdot a t m$ $0.750*atm$ . What is the new volume?