If perimeter of a rectangle is $10 x + 4 y - 8$ $10x+4y-8$ and its breadth is $2 x + y$ $2x+y$ , find its length?

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Answer 1 · 2016-11-28T09:24:54

Length of rectangle in terms of $x$ $x$ and $y$ $y$ is $3 x + y - 4$ $3x+y-4$ .

If the length of a rectangle is $l$ $l$ and breadth is $b$ $b$ , its perimeter is $2 \times (l + b)$ $2xx(l+b)$ .

As breadth is $(2 x + y)$ $(2x+y)$ and perimeter is $10 x + 4 y - 8$ $10x+4y-8$ , we can write this as

$2 \times (l + 2 x + y) = 10 x + 4 y - 8$ $2xx(l+2x+y)=10x+4y-8$ and dividing by $2$ $2$ , we get

$l + 2 x + y = 5 x + 2 y - 4$ $l+2x+y=5x+2y-4$

or $l = 5 x + 2 y - 4 - 2 x - y$ $l=5x+2y-4-2x-y$

i.e. $l = 3 x + y - 4$ $l=3x+y-4$

Hence, length of rectangle in terms of $x$ $x$ and $y$ $y$ is $3 x + y - 4$ $3x+y-4$ .

If perimeter of a rectangle is 10x+4y−810x+4y-8 and its breadth is 2x+y2x+y, find its length?