Question

Question #ffc8d

Answer 1

No, this equation is linear, but does not follow the form "y = kx".

Explanation:

y = kx is the most simple way to look for a direct variation. (although it doesn't have to be linear, it could be y = `ksqrt(x)` or `kx^3` as well!) This function will go through (0,0).

If we solve your equation for y, we see:
`x = (y-3)/5` (multiply both sides by 5)
`5x = y - 3` (add 3 to both sides)
`5x+3 = y`

This linear equation does not have its intercept at the origin (0,0).