At #95.0^@"C"#, a sample of gas has a volume of #"1.55 mL"#. What will the volume be if the gas is cooled to #0.2^@"C"#?

1 Answer
Dec 17, 2016

The final volume will be #"1.15 mL"#.

Explanation:

Your question involves Charles' law, which states that the volume of a gas is directly proportional to its Kelvin temperature, with pressure and mass remaining constant. This means that if the volume increases, the temperature will also increase, and vice versa.

Equation

#V_1/T_1=V_2/T_2#, where #V# is volume, and #T# is temperature in Kelvins.

Known
#V_1="1.55 mL"#
#T_1="95.0"^@"C"+273.15=368.2 "K"#
#T_2="0.2"^@"C"+273.15=273.4 "K"#

Unknown
#V_2#

Solution
Rearrange the equation to isolate #V_2#. Plug in the known values and solve.

#V_2=(V_1T_2)/T_1#

#V_2=(1.55"mL"xx273.4"K")/(368.2"K")="1.15 mL"#