A gas occupies a volume of $12.7 \cdot m L$ $12.7mL$ at $295 \cdot K$ $295K$ in a piston; what volume will it occupy at $284 \cdot K$ $284*K$ ?

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Answer 1 · 2017-08-07T07:39:38

We use old Charles' law..... $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1=V_2/T_2$ , which establishes the influence of absolute temperature on gaseous volume......

We solve for $V_{2} = \frac{V_{1}}{T_{1}} \times T_{2}$ $V_2=V_1/T_1xxT_2$

$\frac{12.7 \cdot m L}{295 \cdot K} \times 284 \cdot K = 12.2 \cdot m L$ $(12.7*mL)/(295*K)xx284*K=12.2*mL$

AS expected, the volume is slightly reduced at slightly reduced temperature.

A gas occupies a volume of 12.7⋅mL12.7*mL at 295⋅K295*K in a piston; what volume will it occupy at 284⋅K284*K?