What is $(4 \times 4 (6 + 4) - 3 (8 + 1) + 2) \div 3 + (5 + 2) (5 + 2) - 2 \times 2 + (42 \div 6) (42 \div 6) + 1$ $(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1$ ?

Question

What is $(4 \times 4 (6 + 4) - 3 (8 + 1) + 2) \div 3 + (5 + 2) (5 + 2) - 2 \times 2 + (42 \div 6) (42 \div 6) + 1$ $(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1$ ?

1 Answer

Impact of this question

1768 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-15T14:52:44

$140$ $140$

Explanation:

Use PEMDAS to help with the order of operations:

P for Parentheses

E for Exponents

MD for Multiplication and Division (left to right)

AS for Addition and Subtraction (left to right)

So we find:

$(4 \times 4 (6 + 4) - 3 (8 + 1) + 2) \div 3 + (5 + 2) (5 + 2) - 2 \times 2 + (42 \div 6) (42 \div 6) + 1$ $(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1$

$= (4 \times 4 (10) - 3 (9) + 2) \div 3 + (7) (7) - 2 \times 2 + (7) (7) + 1$ $=(4xx4(10)-3(9)+2)-:3+(7)(7)-2xx2+(7)(7)+1$

$= (4 \times 40 - 27 + 2) \div 3 + 49 - 2 \times 2 + 49 + 1$ $=(4xx40-27+2)-:3+49-2xx2+49+1$

$= (160 - 27 + 2) \div 3 + 49 - 2 \times 2 + 49 + 1$ $=(160-27+2)-:3+49-2xx2+49+1$

$= (133 + 2) \div 3 + 49 - 2 \times 2 + 49 + 1$ $=(133+2)-:3+49-2xx2+49+1$

$= 135 \div 3 + 49 - 2 \times 2 + 49 + 1$ $=135-:3+49-2xx2+49+1$

$= 45 + 49 - 4 + 49 + 1$ $=45+49-4+49+1$

$= 94 - 4 + 49 + 1$ $=94-4+49+1$

$= 90 + 49 + 1$ $=90+49+1$

$= 139 + 1$ $=139+1$

$= 140$ $=140$

Science

Math

Humanities

... and beyond

What is $(4 \times 4 (6 + 4) - 3 (8 + 1) + 2) \div 3 + (5 + 2) (5 + 2) - 2 \times 2 + (42 \div 6) (42 \div 6) + 1$ $(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is (4×4(6+4)−3(8+1)+2)÷3+(5+2)(5+2)−2×2+(42÷6)(42÷6)+1(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1 ?

1 Answer

Explanation:

Related questions

Impact of this question

What is $(4 \times 4 (6 + 4) - 3 (8 + 1) + 2) \div 3 + (5 + 2) (5 + 2) - 2 \times 2 + (42 \div 6) (42 \div 6) + 1$ $(4xx4(6+4)-3(8+1)+2)-:3+(5+2)(5+2)-2xx2+(42-:6)(42-:6)+1$ ?