Question

Question #2c599

Answer 1

So we know that `root 3x=cxxy^2` where `c=` a constant.

Explanation:

Plug in what we know:

`root3 27=cxx3^2->3=cxx9->c=3/9=1/3`

Now the new value of `y`:

`root3x=1/3xx1.5^2=1/3xx2.25=0.75=3/4`

`->x=(3/4)^3=27/64~~0.42`