A gas at 34 ""^@C expressed a volume of 10*L in a piston; what is the new volume at 48 ""^@C?

1 Answer
May 13, 2017

Old Charles' Law holds that V_1/T_1=V_2/T_2, moles and pressure constant.........

Explanation:

Pressure is a constant here, but we know (or should know) that 1*atm pressure will support a column of mercury that is 760*mm*Hg tall; this relationship is linear: 1/2 an atmosphere will support a column of mercury that is 380*mm*Hg tall. A mercury manometer is thus useful to measure laboratory pressures of confined gases.

We also must employ the absolute temperature scale..........

And so V_2=V_1/T_1xxT_2=(10*L)/(307*K)xx348*K~=11*L