A gas enclosed in piston at $328.2 \cdot K$ $328.2K$ occupies a volume of $3.60 \cdot L$ $3.60L$ . How does the volume change when the gas is cooled to $303.2 \cdot K$ $303.2*K$ ?

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A gas enclosed in piston at $328.2 \cdot K$ $328.2K$ occupies a volume of $3.60 \cdot L$ $3.60L$ . How does the volume change when the gas is cooled to $303.2 \cdot K$ $303.2*K$ ?

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Answer 1 · 2017-05-14T08:31:53

We use old $Charles' Law............ V \propto T$ $"Charles' Law............"VpropT$

Explanation:

If $V \propto T$ $VpropT$ , then $V = k T$ $V=kT$ ; the equation assumes constant pressure, and a given quantity of gas. $T$ $T$ is specified as $absolute temperature$ $"absolute temperature"$ .

If we solve for $k$ $k$ , the $\frac{V}{T} = k$ $V/T=k$ ........

And given constant pressure, a constant quantity of gas:

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1=V_2/T_2$

$V_{2} = \frac{3.60 \cdot L}{328.2 \cdot K} \times 303.2 \cdot K = 3.3 \cdot L$ $V_2=(3.60*L)/(328.2*K)xx303.2*K=3.3*L$ .

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A gas enclosed in piston at $328.2 \cdot K$ $328.2K$ occupies a volume of $3.60 \cdot L$ $3.60L$ . How does the volume change when the gas is cooled to $303.2 \cdot K$ $303.2*K$ ?

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A gas enclosed in piston at 328.2⋅K328.2*K occupies a volume of 3.60⋅L3.60*L. How does the volume change when the gas is cooled to 303.2⋅K303.2*K?

1 Answer

Explanation:

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A gas enclosed in piston at $328.2 \cdot K$ $328.2K$ occupies a volume of $3.60 \cdot L$ $3.60L$ . How does the volume change when the gas is cooled to $303.2 \cdot K$ $303.2*K$ ?