A gas enclosed in piston at #328.2K# occupies a volume of #3.60L#. How does the volume change when the gas is cooled to #303.2*K#?

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Answer 1 · 2017-05-14T08:31:53

We use old #"Charles' Law............"VpropT#

If #VpropT#, then #V=kT#; the equation assumes constant pressure, and a given quantity of gas. #T# is specified as #"absolute temperature"#.

If we solve for #k#, the #V/T=k#........

And given constant pressure, a constant quantity of gas:

#V_1/T_1=V_2/T_2#

#V_2=(3.60*L)/(328.2*K)xx303.2*K=3.3*L#.

A gas enclosed in piston at #328.2*K# occupies a volume of #3.60*L#. How does the volume change when the gas is cooled to #303.2*K#?