Simplify 1024^(-4/5)? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 20, 2017 1024^(-4/5)=1/256 Explanation: 1024^(-4/5) = (2xx2xx2xx2xx2xx2xx2xx2xx2xx2)^(-4/5) = (2^10)^(-4/5) = 2^((10xx(-4/5)) = 2^(-8) = 1/2^8 = 1/256 Answer link Related questions How do you simplify c^3v^9c^-1c^0? How do you simplify (- 1/5)^-2 + (-2)^-2? How do you simplify (4^6)^2 ? How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 ? How do you simplify 4^3·4^5? How do you simplify (5^-2)^-3? How do you simplify and write (-5.3)^0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^2? How do you simplify the expression 2^5/(2^3 times 2^8)? When can I add exponents? See all questions in Exponents Impact of this question 9934 views around the world You can reuse this answer Creative Commons License