$a + \frac{3}{4 b} = 2$ $a+3/(4b)=2$ and $b + \frac{3}{4 a} = 6$ $b+3/(4a)=6$ . How do you find $\frac{b}{a}$ $b/a$ ?

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$a + \frac{3}{4 b} = 2$ $a+3/(4b)=2$ and $b + \frac{3}{4 a} = 6$ $b+3/(4a)=6$ . How do you find $\frac{b}{a}$ $b/a$ ?

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Answer 1 · 2016-03-10T12:18:55

$\frac{b}{a} = 3$ $b/a=3$

Explanation:

If we just examine the first equation:

$\frac{4 a b}{4 b} + \frac{3}{4 b} = 2$ $(4ab)/(4b)+3/(4b)=2$

$\frac{4 a b + 3}{4 b} = 2$ $(4ab+3)/(4b)=2$

The second equation, modified similarly, yields:

$\frac{4 a b + 3}{4 a} = 6$ $(4ab+3)/(4a)=6$

If we take the second equation divided by the first equation, we see that

$\frac{\frac{4 a b + 3}{4 a}}{\frac{4 a b + 3}{4 b}} = \frac{6}{2}$ $((4ab+3)/(4a))/((4ab+3)/(4b))=6/2$

$\frac{4 b}{4 a} = 3$ $(4b)/(4a)=3$

$\frac{b}{a} = 3$ $b/a=3$

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$a + \frac{3}{4 b} = 2$ $a+3/(4b)=2$ and $b + \frac{3}{4 a} = 6$ $b+3/(4a)=6$ . How do you find $\frac{b}{a}$ $b/a$ ?

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Explanation:

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a+34b=2a+3/(4b)=2 and b+34a=6b+3/(4a)=6. How do you find bab/a?

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Explanation:

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$a + \frac{3}{4 b} = 2$ $a+3/(4b)=2$ and $b + \frac{3}{4 a} = 6$ $b+3/(4a)=6$ . How do you find $\frac{b}{a}$ $b/a$ ?