Question

A balloon has a volume of 253.2 mL at 356 K. The volume of the balloon is decreased to 165.4 mL. What is the new temperature?

Answer 1

The new temperature is `"233 K"`.

Explanation:

Charles' law states that when pressure is held constant, temperature and volume are directly proportional. The equation to use is `V_1/T_1V_2/T_2`.

Given
`V_1=252.3cancel"mL"xx(1"L")/(1000cancel"mL")="0.2523 L"`
`T_1="356 K"`
`V_2=165.4cancel"mL"xx(1"L")/(1000cancel"mL")="0.1654 L"`

Unknown
`T_2`

Equation
`V_1/T_1V_2/T_2`

Solution
Rearrange the equation to isolate `T_2`.
`T_2=(T_1V_2)/V_1`

`T_2=((356"K")xx(0.1654cancel"L"))/(0.2523cancel"L")="233 K"`