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A gas at 55.0°C occupies a volume of 3.60 L. What volume will it occupy at 30.0°C?

1 Answer

Mar 25, 2018

$3.33 L$ $"3.33 L"$

Explanation:

For an ideal gas

$V \propto T$ $"V ∝ T"$

$\frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}}$ $"V"_2/"V"_1 = "T"_2/"T"_1$

$V_{1} = 3.60 L$ $"V"_1 = "3.60 L"$
$V_{2} = ?$ $"V"_2 = ?$
$T_{1} = 55.0°C = (55.0 + 273)K = 328 K$ $"T"_1 = "55.0°C" = "(55.0 + 273)K" = "328 K"$
$T_{2} = 30.0°C = (30.0 + 273)K = 303 K$ $"T"_2 = "30.0°C" = "(30.0 + 273)K" = "303 K"$

$"V"_2 = "V"_1 × "T"_2/"T"_1 = "3.60 L" × (303 cancel"K")/(328 cancel"K") = "3.33 L"$

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