A pyramid has a parallelogram shaped base and a peak directly above its center. Its base's sides have lengths of #7 # and #3 # and the pyramid's height is #6 #. If one of the base's corners has an angle of #pi/3#, what is the pyramid's surface area?
1 Answer
Sep 13, 2016
Explanation:
Total surface area = base area (a1) + side area 1 (a2) + side area 2 (a3).
1) base area (a1) = parallelogram area = BxxH
2) side area 1 (a2)
3) side area 2 (a3)
Fianlly, total surface area = a1+a2+a3