At 35°C a sample of a fixed amount of ideal gas occupies 150. mL at a pressure of 3.50 atm. What would be its volume at the same pressure and 105°C?

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At 35°C a sample of a fixed amount of ideal gas occupies 150. mL at a pressure of 3.50 atm. What would be its volume at the same pressure and 105°C?

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Answer 1 · 2015-03-28T12:52:25

The volume at 105 °C will be 184 mL.

This is a problem involving Charles' Law.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1 = V_2/T_2$

In your problem,

$V_{1} = 150. mL$ $V_1 = "150. mL"$ ; $T_{1} = (35 + 273.15) K = 308.15 K$ $T_1 = "(35 + 273.15) K" = "308.15 K"$
$V_{2} = ?$ $V_2 = "?"$ ; $T_{2} = (105 + 273.15) K = 378.15 K$ $T_2 = "(105 + 273.15) K" = "378.15 K"$

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1 = V_2/T_2$

$V_2 = V_1 × T_2/T_1 = "150. mL" × (378.15 cancel("K"))/(308.15 cancel("K")) = "184 mL"$

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At 35°C a sample of a fixed amount of ideal gas occupies 150. mL at a pressure of 3.50 atm. What would be its volume at the same pressure and 105°C?

1 Answer

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