For the direct variation y = (-3/8) when x = (-2/3), how do you find the constant of variation and find the value of y when x = 3?

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For the direct variation y = (-3/8) when x = (-2/3), how do you find the constant of variation and find the value of y when x = 3?

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Answer 1 · 2017-06-08T10:13:12

$y = 1 \frac{11}{16}$ $y =1 11/16$

Explanation:

$x \propto y or x = k \cdot y or k = \frac{x}{y} or k = \frac{- \frac{2}{3}}{- \frac{3}{8}} = \frac{16}{9}; k$ $x prop y or x = k *y or k = x/y or k = (-2/3)/(-3/8) = 16/9 ; k$ is a constant. The variation equuation is $\frac{x}{y} = \frac{16}{9}; x = 3; y = ?$ $x/y=16/9 ; x=3 ; y= ?$

$\frac{3}{y} = \frac{16}{9} or y = \frac{9 \cdot 3}{16} = \frac{27}{16} = 1 \frac{11}{16}$ $3/y=16/9 or y = (9*3)/16 =27/16 = 1 11/16$ [Ans]

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For the direct variation y = (-3/8) when x = (-2/3), how do you find the constant of variation and find the value of y when x = 3?

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Explanation:

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