Given the matrices $A=[(5,7),(-1,6), (3,-9)], B=[(8,3), (5,1), (4,4)], C=[(0,4),(-2,5), (7,-1)], D[(6,2), (9,0), (-3,0)]$ , how do you find 6B-2A?

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Answer 1 · 2016-11-14T14:57:40

The answer is $=((38,4),(32,-6),(18,42))$

$A=((5,7),(-1,6),(3,-9))$

Therefore, $2A=2*((5,7),(-1,6),(3,-9))=((10,14),(-2,12),(6,-18))$

$B=((8,3),(5,1),(4,4))$

Therefore, $6B=6*((8,3),(5,1),(4,4))=((48,18),(30,6),(24,24))$

So, $6B-2A=((48,18),(30,6),(24,24))-((10,14),(-2,12),(6,-18))$

$= ((38,4),(32,-6),(18,42))$

Given the matrices A=[(5,7),(-1,6), (3,-9)], B=[(8,3), (5,1), (4,4)], C=[(0,4),(-2,5), (7,-1)], D[(6,2), (9,0), (-3,0)]A=[(5,7),(-1,6), (3,-9)], B=[(8,3), (5,1), (4,4)], C=[(0,4),(-2,5), (7,-1)], D[(6,2), (9,0), (-3,0)], how do you find 6B-2A?