How can I draw the following amides: N-ethylbutanamide, N-propylpentanamide, N,3-dimethylhexanamide?

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Answer 1 · 2015-08-11T16:49:59

You draw the base structure, then you add the substituents in the appropriate locations.

1. N-Ethylbutanamide

The base name tells you that this molecule has a four-carbon chain with an amide group.

Its skeleton structure is ${C-C-C-CONH}_{2}$ $"C-C-C-CONH"_2$ .

The carbonyl group is automatically $C-1$ $"C-1"$ .

A substituent on the $N$ $"N"$ atom is indicated by the prefix N-.

In this case, we have an ethyl group on the $N$ $"N"$ atom, so the structure is

2. N-Propylpentanamide

Here, we have a five-carbon amide with a propyl group on the $N$ $"N"$ atom.

The structure is

(from opsin.ch.cam.ac.uk)

3. N,3-Dimethylhexanamide

Here, we have a six-carbon amide with one methyl group on the $N$ $"N"$ atom and another methyl group on $C-3$ $"C-3"$ of the main chain.

The structure is

(from opsin.ch.cam.ac.uk)