How can I draw the following ethers: 1-propoxypentane, 2-ethoxybutane, 1-methoxy-4-chlorohexane, and 3-butoxy-2,4-dimethyloctane?

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Answer 1 · 2015-06-16T21:06:33

You draw the main chain. Then you attach the alkoxy group to the appropriate carbon atom.

1-Propoxypentane

Pentane is a chain of 5 carbon atoms.

The propoxy group is a 3-carbon chain with an $O$ $"O"$ atom at $C-1$ $"C-1"$ .

Draw a chain of five carbon atoms and attach the 1-propoxy group to $C-1$ $"C-1"$ of the chain.

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2-Ethoxybutane

Attach an ethoxy group to $C-2$ $"C-2"$ of a butane chain.

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4-Chloro-1-methoxyhexane

Draw a 6-carbon chain. Attach a methoxy group to $C-1$ $"C-1"$ and a $Cl$ $"Cl"$ atom to $C-4$ $"C-4"$ .

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3-Butoxy-2,4-dimethyloctane

Draw an 8-carbon chain. Attach a butoxy group to $C-3$ $"C-3"$ and methyl groups to $C-2$ $"C-2"$ and $C-4$ $"C-4"$ .

enter image source here