How can you use trigonometric functions to simplify $12 e^( ( 19 pi)/12 i )$ into a non-exponential complex number?

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Answer 1 · 2018-04-19T09:16:41

$3sqrt6-3sqrt2-i(3sqrt6+3sqrt2)$

We can turn into $re^(itheta)$ into a complex number by doing: $r(costheta+isintheta)$

$r=12$ , $theta=(19pi)/12$

$12(cos((19pi)/12)+isin((19pi)/12))$

$3sqrt6-3sqrt2-i(3sqrt6+3sqrt2)$

How can you use trigonometric functions to simplify 12 e^( ( 19 pi)/12 i ) 12 e^( ( 19 pi)/12 i ) into a non-exponential complex number?