Question

How can you use trigonometric functions to simplify `15 e^( ( pi)/2 i )` into a non-exponential complex number?

Answer 1

I found `15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i`

Explanation:

You can convert it into a complex number in trigonometric form first remembering that:
`rhoe^(thetai)=rho[cos(theta)+isin(theta)]`
In your case:
`15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i`