How can you use trigonometric functions to simplify $17 e^{\frac{4 π}{3} i}$ $17 e^( ( 4 pi)/3 i )$ into a non-exponential complex number?

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How can you use trigonometric functions to simplify $17 e^{\frac{4 π}{3} i}$ $17 e^( ( 4 pi)/3 i )$ into a non-exponential complex number?

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Answer 1 · 2016-02-17T06:51:49

$-$ $-$ 17/2 ( 1 + $\sqrt{}$ $sqrt$ 3 i)

Explanation:

r = 17, $θ$ $theta$ = $4 \frac{π}{3}$ $4pi/3$
In non-exponential form x + i y,
x = r cos $θ$ $theta$ and y = r sin $θ$ $theta$ .
Also, cos ( $π$ $pi$ + $θ$ $theta$ ) = $- cos θ$ $- cos theta$ and sin ( $π$ $pi$ + $θ$ $theta$ ) = $- sin θ$ $- sin theta$ .

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How can you use trigonometric functions to simplify $17 e^{\frac{4 π}{3} i}$ $17 e^( ( 4 pi)/3 i )$ into a non-exponential complex number?

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How can you use trigonometric functions to simplify 17e4π3i 17 e^( ( 4 pi)/3 i ) into a non-exponential complex number?

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How can you use trigonometric functions to simplify $17 e^{\frac{4 π}{3} i}$ $17 e^( ( 4 pi)/3 i )$ into a non-exponential complex number?