How can you use trigonometric functions to simplify $25 e^{\frac{17 π}{12} i}$ $25 e^( ( 17 pi)/12 i )$ into a non-exponential complex number?

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Answer 1 · 2016-01-19T18:20:50

$25 [cos (\frac{17 π}{12}) + i sin (\frac{17 π}{12})]$ $25 [ cos ((17 pi)/12) + i sin(( 17pi)/12) ]$

Since $e^{i x} = cos x + i sin x$ $e^(ix)= cos x +i sin x$ ,

the given expression would be $25 [cos (\frac{17 π}{12}) + i sin (\frac{17 π}{12})]$ $25 [ cos ((17 pi)/12) + i sin(( 17pi)/12) ]$

How can you use trigonometric functions to simplify 25 e^( ( 17 pi)/12 i ) 25e17π12i 25 e^( ( 17 pi)/12 i ) into a non-exponential complex number?