How can you use trigonometric functions to simplify $28 e^{\frac{π}{8} i}$ $28 e^( ( pi)/8 i )$ into a non-exponential complex number?

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Answer 1 · 2016-02-11T22:46:00

$28 e^{\frac{π}{8} i} = 28 cos (\frac{π}{8}) + i sin (\frac{π}{8})$ $28e^(pi/8i)=28cos(pi/8)+i sin(pi/8)$

$e^{θ i} = cos (θ) + i sin (θ)$ $e^(theta i)=cos(theta)+i sin(theta)$

so $28 e^{\frac{π}{8} i} = 28 cos (\frac{π}{8}) + i sin (\frac{π}{8})$ $28e^(pi/8i)=28cos(pi/8)+i sin(pi/8)$

How can you use trigonometric functions to simplify 28 e^( ( pi)/8 i ) 28eπ8i 28 e^( ( pi)/8 i ) into a non-exponential complex number?