How can you use trigonometric functions to simplify $7 e^{\frac{7 π}{6} i}$ $7 e^( ( 7 pi)/6 i )$ into a non-exponential complex number?

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How can you use trigonometric functions to simplify $7 e^{\frac{7 π}{6} i}$ $7 e^( ( 7 pi)/6 i )$ into a non-exponential complex number?

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Answer 1 · 2016-01-05T01:04:27

It is $- \frac{7}{2} \cdot (\sqrt{3} + i)$ $-7/2*(sqrt3+i)$

Explanation:

It is

$7 \cdot e^{7 \cdot π \cdot \frac{i}{6}} = 7 \cdot (cos (7 \cdot \frac{π}{6}) + i sin (7 \cdot \frac{π}{6})) = 7 \cdot (- \frac{\sqrt{3}}{2} - \frac{1}{2} \cdot i)$ $7*e^(7*pi*i/6)=7*(cos(7*pi/6)+isin(7*pi/6))=7*(-sqrt3/2-1/2*i)$

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How can you use trigonometric functions to simplify $7 e^{\frac{7 π}{6} i}$ $7 e^( ( 7 pi)/6 i )$ into a non-exponential complex number?

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Explanation:

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How can you use trigonometric functions to simplify 7e7π6i 7 e^( ( 7 pi)/6 i ) into a non-exponential complex number?

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How can you use trigonometric functions to simplify $7 e^{\frac{7 π}{6} i}$ $7 e^( ( 7 pi)/6 i )$ into a non-exponential complex number?