How do I find all real and complex zeros of $x^{2} + 1$ $x^2+1$ ?

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Answer 1 · 2014-09-25T21:04:06

You find the zeros by setting the expression equal to zero.

$x^{2} + 1 = 0$ $x^2+1=0$

Then solve for $x$ $x$

$x^{2} = - 1$ $x^2=-1$

$\sqrt{x^{2}} = \pm \sqrt{- 1}$ $sqrt(x^2)=+-sqrt(-1)$

$x = \pm i$ $x=+-i$

This expression has 2 imaginary roots $+ i$ $+i$ and $- i$ $-i$ .

How do I find all real and complex zeros of x^2+1x2+1x^2+1?