How do I find the limit as $x$ $x$ approaches negative infinity of $sin x$ $sinx$ ?

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Answer 1 · 2015-07-05T16:34:50

Limit does not exist

$Lim x-> -oo$ sin x = $Lim x->oo$ sin(-x)= $Lim x->oo$ -sinx

As $x->oo$ , sin x will oscillate between -1 and +1 and will not converge to any particular value. Hence this limit would not exist.

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