How do you add $(2+i)+(5+3i)$ in trigonometric form?

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Answer 1 · 2016-03-31T02:32:03

$7+4i=sqrt65[cos(tan^-1 (4/7))+i sin (tan^-1 (4/7))]$

From the given
$(2+i)+(5+3i)$

$(2+5)+(i+3i)$

$7+4i$

in Trigonometric Form

$a+bi=sqrt(a^2+b^2)[cos (tan^-1 (b/a))+i sin (tan^-1 (b/a))]$

$7+4i=sqrt65[cos(tan^-1 (4/7))+i sin (tan^-1 (4/7))]$

God bless....I hope the explanation is useful.

How do you add (2+i)+(5+3i)(2+i)+(5+3i) in trigonometric form?