How do you add $(- 4 + 3 i) + (- 1 + i)$ $(-4+3i)+(-1+i)$ in trigonometric form?

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Answer 1 · 2017-03-21T04:13:13

$\Rightarrow 4 i - 5$ $rArr4i-5$

$(- 4 + 3 i) + (- 1 + i)$ $(-4+3i)+ (-1+i)$

$\Rightarrow - 4 + 3 i + - 1 + i$ $rArr-4+3i+ -1+i$

$\Rightarrow - 5 + 3 i + i$ $rArr-5+3i+i$

$\Rightarrow - 5 + i (3 + 1)$ $rArr-5+i(3+1)$

$\Rightarrow 4 i - 5$ $rArr4i-5$

How do you add (−4+3i)+(−1+i)(-4+3i)+(-1+i) in trigonometric form?